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   GMAT Geometry Guide
Chapter 1: Angles and Lines
Chapter 2: Intersecting Angles
Chapter 3 Triangles
Chapter 4: Circles
Chapter 5: Perimeters & Areas
Chapter 6: Solids
Chapter 7: Coordinate Geometry

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   Geometry Chapter 5: Perimeters and Areas
Table of Contents  
 

The perimeter of a figure is the distance around the figure. The perimeter, P, and area, A, of common figures are shown.



P= 2r
A=
r

 


 Rectangle



P= 2h + 2b

A=bh


 Square




P = 4h
A = h

 


 Right triangle



A = bh/2


Triangle

A = bh/2


Parallelogram




A = bh

 

 

Calculating Diagonals  
Courtesy of Knewton (click for more information)



Symmetry

Courtesy of Knewton (click for more information)


Example 1 (easy)

What is the radius of a circle if its circumference is numerically equal to twice its area?

 


Solution

The perimeter is the same as the circumference = 2r. The area is r, so that
2r = 2(r ); therefore, r must equal 1.





Example 2 (medium)

An automobile travels 2 miles. How many rotations does a 14-inch radius tire make (use 22/7 for )?


 

Solution

The circumference of a tire is 2r = 2 × 14 = 28 inches. First, make the units commensurate by converting miles to inches (12 inches in a foot, 5280 feet in a mile).

No. of rotations =
(2 miles × 5280 ft/mile × 12 inches/ft)
28
Substitute 22/7 for (we put 7 on top and 22 on bottom)
(2 × 5280 × 12 × 7 )
28 × 22
Cancel out 2 into 22, 7 into 28 to make 4 and then that 4 into 12.
(2 × 5280 × 312 × 7 )
28 × 22 11

(5280 × 3)
= 1440
11

In the above, we simplified by canceling out common factors and then multiplied and divided. It is important to first simplify to save time in the final step.



Example 3

A square is inscribed in a circle of radius 10. Determine the ratio of the area of the circle to the area of the square.




Solution



First, sketch the figure. The area of the circle is r = 100. That's easy.

Now let's go over the area of the circle. The diameter is 20, which is also equal to the diagonal of the square. The diagonal of the square is also the hypotenuse of a right triangle inside of the square, a 45-45 triangle.

The legs of the triangle are equal so that b = 20/. Since it is a 45/45 right triangle, the legs are equal to the hypotenuse /. The area of the square is the leg squared (20 / ) = 200. The ratio of the areas is:

Area circle/Area square = 100/200 =/2


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  Contents of Geometry Chapter: Table of Contents
Chapter 1: Angles and Lines
  Chapter 2: Intersecting Angles
  Chapter 3: Triangles
  Chapter 4: Circles
  Chapter 5: Perimeters & Areas
  Chapter 6: Solids
  Chapter 7:
Coordinate Geometry
 
 Chapter 6: Solids

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