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   GMAT Geometry Guide
Chapter 1: Angles and Lines
Chapter 2: Intersecting Angles
Chapter 3 Triangles
Chapter 4: Circles
Chapter 5: Perimeters & Areas
Chapter 6: Solids
Chapter 7: Coordinate Geometry

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   Geometry Chapter 6: Solids
Table of Contents  
 

There are two solids that interest us in preparing for the test. They are the rectangular solid (a box) and a circular cylinder. A cube is a special rectangular box whose sides are all equal. The volume of a box is the product of its three sides: V = bwh (base × width × height) . The volume of a circular cylinder is the area of the base times the height: V = rh (base circle × height).

The surface area of a cube is 6 × (area of one side) since all six sides have the same area. The surface area of a cylinder is composed of the top and bottom circular areas and the area around the cylinder. The top and bottom are simply 2 × × r . The area of the side is 2 × × radius × height.

Box



V = bhw

 

Cylinder



V =rh



How to calculate a rectangular solid
Courtesy of Knewton (click for more information)

How to calculate cylinder volume
Courtesy of Knewton (click for more information)


Spheres

Courtesy of Knewton (click for more information)



Example 1 (easy)

How many liters does it take to fill a box that is 2m by 20 cm by 20 mm?




Solution

There are 1000 liters in a cubic meter. Hence, we find the volume in cubic meters and multiply by 1000. The volume is

V = bwh
   = 2 × 0.2 × 0.02 = 0.008m

1000 liters/m ×  0.008m = 8 liters


Example 2 (easy)

It takes about 7.5 gallons to fill a volume of one cubic foot. How many gallons are needed to fill a cylinder 2 ft high and 28 inches in radius (=22/7)?




Solution

The volume of a cylinder is the area of its circular base times its height:

V = rh
= 22/7
r = 28 inches, or 28/12 feet (divide 28 by 12 to convert) or 7/3 (factor out the 4), r = 49/9
h = 2, height equals 2.

Now let's plug the numbers into the equation: V =rh
= 22/7 × (49/9) × 2 =
cancel out the 7 under 22 and the 49 above 9 and multiply

= 308 / 9ft

Since it takes 7.5 gallons to fill one cubic foot, multiply the cubic area by 7.5.

= 308/9 × 7.5 gallons = 256 2/3 gallons





Example 3 .

A gallon of paint covers 400 ft of wall area. How many gallons are required to paint the walls of a building with perimeter 200 ft and height 10 ft (assuming there are no windows)?



Solution


The perimeter is the distance around the building, that is, the length of the rectangles that make up its sides. Since each rectangular side is assumed to be 10 ft high, the total area is:

A = bh = 200 × 10 = 2000ft

Number of gallons required = 2000/400 = 5

Note: the shape of the building makes no difference here. The building could be circular (think of taking the wrapper off of a bottle to make a rectangle).

 

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  Contents of Geometry Chapter: Table of Contents
Chapter 1: Angles and Lines
  Chapter 2: Intersecting Angles
  Chapter 3: Triangles
  Chapter 4: Circles
  Chapter 5: Perimeters & Areas
  Chapter 6: Solids
  Chapter 7:
Coordinate Geometry
 
 Chapter 7: Coordinate Geometry

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