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 Post subject: GRE Algebra
PostPosted: Thu Nov 15, 2012 5:43 pm 
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Joined: Sun May 30, 2010 3:15 am
Posts: 424
Please explain how this equation works out:

s² / (s²√3 / 4) = 4s² / (s²√3) = 4 / √3 = (4√3) / 3

I am with each step, crossing out the s², and then you have 4 / √3. But how does 4 / √3 turn into 4√3 / 3? Isn't that an extra three?

I think what I really need is a lesson in multiplying/dividing by radicals. I always seem to mess them up and the only thing I ever read is telling me to group radicals together and treat regular numbers separately. I do not see anything that goes into depth. Please help!


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 Post subject: Re: GRE Algebra
PostPosted: Thu Nov 15, 2012 6:03 pm 
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