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GRE Arithmetic (Select One) http://www.800score.com/forum/viewtopic.php?f=12&t=3347 
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Author:  questioner [ Tue Sep 14, 2010 2:58 am ] 
Post subject:  GRE Arithmetic (Select One) 
A prize of $600 is to be distributed among 20 winners, each of whom must be awarded at least $20. If 2/5 of the prize will be distributed to 3/5 of the winners, what is the greatest possible individual award? A. $20 B. $25 C. $45 D. $220 E. $300 (D) We are told that 2/5 of the prize is distributed to 3/5 of the winners: 2/5 of the prize = 2/5 × $600 = $240. 3/5 of the winners = 3/5 × 20 = 12 winners. Since $240/12 = $20, we know that each of these people received the minimum of $20. The remaining $360 will be divided among the 8 remaining winners. For one of these winners to receive the greatest possible award, the other seven winners must receive the minimum $20. These seven winners receive a total of: 7 × $20 = $140. The eighth winner would receive all the remaining prize money:$360 – $140 = $220. The correct answer is choice (D).  In the above question, you calculate a minimum of $20 to be distributed among the "12" people to whom $240 would be distributed. Then you claim that that $20 is also a minimum for the remaining 8 winners. It seems that the minimum amount that each of the remaining 8 winners could receive is 360/8 = $45. So for one of these 8 winners to receive the greatest possible award, the remaining 7 winners must receive 7 × $45 (not $20) = $315. So the eighth winner would receive the remaining of the prize: $360 – $315 = $45 ($240 + $315 + $45 = $600) Please explain if my logic is flawed. Thank you. 
Author:  Gennadiy [ Tue Sep 14, 2010 3:24 am ] 
Post subject:  Re: math (test 4, question 5): arithmetic, logic. 
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