For each of the three circles shown above, the diameter of the smaller circle is equal to the radius of the larger. If the area of the largest circle is 52π square inches greater than the area of the shaded region, then what is the area of the shaded region in square inches?

A. 4π

B. 6π

C. 12π

D. 16π

E. 26π

(C) Let’s denote the radius of the smallest circle by

*x* inches. Then the radius of the black circle is 2

*x* inches and the radius of the largest circle is 4

*x* inches.

Now we use the formula π

*r*² to find the areas of the circles. The areas of the circles are π

*x*², π(2

*x*)², and π(4

*x*)² square inches respectively. The area of the shaded region is the area of the black circle minus the area of the smallest circle. It equals π(2

*x*)² – π

*x*² = 3π

*x*² square inches.

We know that the area of the largest circle is 52π square inches greater than the area of the shaded region. Let’s write it down as the following equation:

π(4

*x*)² = 52π + 3π

*x*²

divide the both sides by π

16

*x*² = 52 + 3

*x*²

13

*x*² = 52

*x*² = 4

*x* = 2

We know that the area of the shaded region is 3π

*x*² = 12π square inches. The correct answer s C.

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The question does not say the larger circle passes through the centre of the largest circle. So, the radius of the largest circle cannot be said to be 4*x*.