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Post subject: GMAT Algebra (Data Sufficiency) Posted: Mon Jan 24, 2011 4:55 pm 

Joined: Sun May 30, 2010 3:15 am Posts: 424

If a x² + b x³ = 5, where a and b are nonzero numbers, what is the value of a + b? (1) a x² = a (2) b x³ = b A. Statement (1) BY ITSELF is sufficient to answer the question, but statement (2) by itself is not. B. Statement (2) BY ITSELF is sufficient to answer the question, but statement (1) by itself is not. C. Statements (1) and (2) TAKEN TOGETHER are sufficient to answer the question, even though NEITHER statement BY ITSELF is sufficient. D. Either statement BY ITSELF is sufficient to answer the question. E. Statements (1) and (2) TAKEN TOGETHER are NOT sufficient to answer the question, meaning that further information would be needed to answer the question. (B) The important thing to remember here is that, when a number is squared, it will always result in a positive, regardless of whether the original number was negative or positive. This is not the case with a number that is cubed. A cube will only be positive if the original integer was positive; otherwise, it will be negative. That having been said, statement (1) is insufficient. While we know that x can be nothing other than 1 or 1 in order for a x² to equal a, we are not told specifically if x is 1 or 1. Statement (2), however, is sufficient. Because x is cubed, we know that it had to be 1 from the beginning. Statement (2) tells us that a + b = 5. The answer is (B). For more information on this type of questions, order the online prep course by clicking the following link: http://www.800score.com/ordercourse.html The right answer is D. ax² = a, so x² = 1, so x = 1. And so it is similar to statement (2).


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Gennadiy

Post subject: Re: math (test 1, question 28): algebra. Posted: Mon Jan 24, 2011 5:12 pm 

Joined: Sun May 30, 2010 2:23 am Posts: 498

ax² = a x² = 1 x = 1 or x = 1
If x = 1, then ax² + bx³ = a × 1² + b × 1³ = a + b = 5
If x = 1, then ax² + bx³ = a × (1)² + b × (1)³ = a – b = 5 But we don't know what a + b equals to in this case (if x = 1).
Therefore statement (1) by itself is NOT sufficient.


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Gennadiy

Post subject: Re: math (test 1, question 28): algebra. Posted: Mon Feb 28, 2011 2:44 pm 

Joined: Sun May 30, 2010 2:23 am Posts: 498

The values and 1 are equal. The second statement yields x³ = 1. This equation has only one solution: x = ³√1 = 1.


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questioner

Post subject: Re: math (test 1, question 28): algebra. Posted: Thu Sep 01, 2011 12:55 pm 

Joined: Sun May 30, 2010 3:15 am Posts: 424

In case of 1, if x is 1, then we get a – b = 5 and when x is 1, we get a + b =5. Since we get only 1 value of a + b from (1), I feel the answer to this should be D.


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Gennadiy

Post subject: Re: math (test 1, question 28): algebra. Posted: Thu Sep 01, 2011 1:21 pm 

Joined: Sun May 30, 2010 2:23 am Posts: 498

Quote: Since we get only 1 value of a + b from (1) The situation when x is 1 does NOT give us any specific value of a + b. It gives only the value of a – b. This is NOT sufficient. For example, at least two of the possible variants are: If a = 4, b = 5, then a – b = 1, a + b = 9. If a = 5, b = 6, then a – b = 1, BUT a + b = 11. Therefore statement (1) does NOT give us a definite value of a + b.


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questioner

Post subject: Re: math (test 1, question 28): algebra. Posted: Tue Sep 20, 2011 5:23 pm 

Joined: Sun May 30, 2010 3:15 am Posts: 424

a, b and x could be rational numbers, it is not mentioned that they are integers. Hence, the inference that x could only be 1 or 1 is wrong; e.g. x = 1/2, a = 4 and b = 32.


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Gennadiy

Post subject: Re: math (test 1, question 28): algebra. Posted: Tue Sep 20, 2011 5:32 pm 

Joined: Sun May 30, 2010 2:23 am Posts: 498

questioner wrote: a, b and x could be rational numbers, it is not mentioned that they are integers. Hence, the inference that x could only be 1 or 1 is wrong; e.g. x = 1/2, a = 4 and b = 32. The proposed values do NOT fit in any statement: Statement (1) will transform into 4 × (1/2)² = 4. This is NOT correct. Statement (2) will transform into 32 × (1/2)³ = 32. This is NOT correct. The basic question statement does NOT specify that x is an integer, but each additional statement gives us some specific possible values of x. Statement (1) yields x = 1 and x = 1. Statement (2) yields x = 1 only.


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cjuarezh

Post subject: Re: GMAT Algebra (Data Sufficiency) Posted: Tue Aug 07, 2012 2:36 am 

Joined: Tue Aug 07, 2012 2:26 am Posts: 1

I desagree with the given answer, we have:
If ax² + bx³ = 5, where a and b are nonzero numbers, what is the value of a + b? (1) ax² = a (2) bx³ = b
I agree that with (1) we cannot answer the question, but (2) isn't enough either.
number 2 says that x³ = 1 (with b nonzero), which has 3 solutions, not 1:
x³  1 = 0 (x – 1) × (x² + x + 1)=0 Either (x – 1) = 0 or (x² + x + 1) = 0. Only x – 1 = 0 gives x = 1. But the 3 solutions are:
1, 1/2 + (√3 / 2) × i, 1/2 – (√3 / 2) × i
The second and third solution, when squared, don't equal 1, so we need the first statement to know that x can't take these values. Therefore, the answer is C and not B.


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Gennadiy

Post subject: Re: GMAT Algebra (Data Sufficiency) Posted: Wed Aug 08, 2012 1:20 pm 

Joined: Sun May 30, 2010 2:23 am Posts: 498

Quote: But the 3 solutions are:
1, 1/2 + (√3 / 2) × i, 1/2 – (√3 / 2) × i Your solution would be true, if x were a complex variable. But x is a real variable, not a complex one. NEVER assume in GMAT that we deal with complex numbers (variables). ALWAYS assume that a number (variable) is a real number, if nothing else is stated.


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