In the diagram above, BD = 8, AB = 6, and ED = 5. What is the length of AE?

A. 3

B. 4

C. 5

D. 7

E. 10

(C) Use this link for a flash video web page explanation:

http://www.800score.com/explanations/GMAT_MATH_T1_Q6_Easy.htmlWe are given that BD = 8, AB = 6, and ED = 5. Let's break this problem down into a few steps.

1) Since triangle ABD is a right triangle where lengths of the two shorter sides are in the ratio of 4 to 3, the triangle must be a 3-4-5 right triangle (a common right-triangle type).

2) We can find the length of AD.

AB = 3 × 2 = 6

BD = 4 × 2 = 8

Therefore, AD = 5 × 2 = 10.

3) Since AE + ED = AD, AE + 5 = 10

4) AE must equal 5.

The correct answer is choice (C).

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I used this formula. Area of a triganle will be A = (1/2)*bh*. And we know BD = 8, AB = 6, ED = 5.

Therefore Area = 1/2 × 8 × 6 = 24.

We need the parameter of the diagram which is P = BD + AB + ED + AE, AE is unknown.

P = 8 + 6 + 5 + AE.

However we know the area of the entire diagram. From adding the

parimteter p = 8 + 6 + 5 = 19

Subtracting parimeter from Area 24 – 19 = 5 this will represent AE. Therefore, AE = 5.

I know this can be represented in a better way or correct way..

Thank you...