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Author:  questioner [ Mon Jun 07, 2010 12:48 am ]
Post subject:  GMAT Geometry

The operation above rotates the regular pentagon clockwise by (72n) degrees from its center. What replaces the initial b position when n = 4?
A. a
B. b
C. c
D. d
E. e

(C) Think of the polygon as you would a wheel being rotated at its center. A wheel sweeps a 360º angle everytime it returns to its initial positon. Since this is a regular pentagon, we can increment our rotations by dividing 360/5 = 72.

So everytime the center spins 72º clockwise, the polygon moves by one vertex. So, when n = 4 the pentagon rotates by 4 vertices and the initial b position is replaced by c or answer choice (C).

An alternative way to consider the problem is to realize that everytime n = 5, it returns to its original configuration. So, when n = 4, the position is occupied by the vertex that is one vertex away in the clockwise direction because it lags by one 72º turn.
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"Since this is a regular pentagon, we can increment our rotations by
dividing 360/5 = 72. So everytime the center spins 72º clockwise, the polygon moves by one vertex."
Doesn't pentagon has 540 degrees?

Author:  Gennadiy [ Mon Jun 07, 2010 1:15 am ]
Post subject:  Re: Math (test 1, question 9): geometry (normal)

The sum of internal pentagon angles is 540 degrees indeed, but 360 degrees - is "full rotation angle" when a point on a circle returns to its own position.

So in the statement
"Since this is a regular pentagon, we can increment our rotations by dividing 360/5 = 72. So everytime the center spins 72º clockwise, the polygon moves by one vertex."
we note and use the statement that it is a REGULAR pentagon. I'd like to bring your attention to the term "REGULAR", because regular polygons can be inscribed in a circle and have vertexes "evenly distributed" on this circle.

Following the same logic it will be true for any REGULAR polygon of n sides that by turning (360/n) degrees it rotates by one vertex.

 Author: questioner [ Mon Jun 07, 2010 2:57 pm ] Post subject: Re: Math (test 1, question 9): geometry, polygon The operation above rotates the regular pentagon clockwise by (72n) degrees from its center. What replaces the initial b position when n = 19?A. aB. bC. cD. dE. eRight Answer is (C).----------Since the rotation is clockwise and the position b is 72 degrees short of returning to its original configuration, shouldn't its position be at a? (c would replace b at 21n)

Author:  Gennadiy [ Mon Jun 07, 2010 3:05 pm ]
Post subject:  Re: Math (test 1, question 9): geometry, polygon

Imagine that we rotated the pentagon 20 × 72º clockwise. That makes it look the same:

If we rotate it (1 × 72) more degrees clockwise then it will look:

We see that in this case (n = 21) point a stands at original position of point b.

If we rotate (1 × 72) less degrees clockwise than (20 × 72º) clockwise turn then in this case it will look:

For better understanding, please, take a look at this animation: