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 Author: questioner [ Sun Aug 22, 2010 1:19 pm ] Post subject: GMAT Coordinate Geometry The two lines y = x and x = -4 intersect on the coordinate plane. What is the value of the area of the figure formed by the intersecting lines and the x-axis?A. √(46)/3B. 4√2C. 8D. 8√2E. 16(C) The lines intersect at the point (-4, -4) and form a right triangle whose base length and height are both equal to 4. As you know, the area of a triangle is equal to one half the product of its base length and height:A = (1/2) × bh = (1/2) × (4 × 4) = 8So the area is 8. The correct answer is C.-------------Hi, is there a pictorial representation of the triangle that is formed from the above equation?Thanks.

Author:  Gennadiy [ Sun Aug 22, 2010 1:30 pm ]
Post subject:  Re: GMAT Coordinate Geometry

Here it is:

Triangle ABC is the right triangle (angle ABC = 90 degrees).
AB = 4
BC = 4

 Author: questioner [ Tue Nov 09, 2010 5:22 pm ] Post subject: Re: GMAT Coordinate Geometry Hello,Based on the information in the stem, to me, the figure that is formed is a square and not a triangle. Since x = -4 forms a straight line parallel to the x-axis and y = x, which translates to y = -4 forms a straight line parallel to the y axis. They both meet at the coordinate (-4.-4), but again, using the x-axis, x = -4 and y = -4 the shape is that of a square not a triangle. Am I missing something?

Author:  Gennadiy [ Tue Nov 09, 2010 5:35 pm ]
Post subject:  Re: GMAT Coordinate Geometry

THE PROPER PICTURE for the question is posted above in this topic.

Note, that the line x = -4 is parallel to the y-axis and crosses the x-axis at the point (-4, 0).

The line y = x and the line y = -4 are different lines. These two lines cross at the point (-4, -4), which happens to be the crossing point of the lines y = x and x = -4 as well.

The following picture demonstrates that the lines y = x and y = -4 are different:

THE PROPER PICTURE for the question is posted above in this topic.