800score.comhttp://www.800score.com/forum/ GMAT Data Analysishttp://www.800score.com/forum/viewtopic.php?f=3&t=86 Page 1 of 1

Author:  questioner [ Sun Nov 14, 2010 3:36 am ]
Post subject:  GMAT Data Analysis

The above graph lists the monthly sales (in \$100,000 increments) at a car dealership. For January and February, the dealership had two sales agents. The dealership added a sales agent in March and one more in May. What was the percent increase in sales per agent in June compared to January?

A. 50%
B. 100%
C. 125%
D. 200%
E. 400%

(B) In January, the dealership had 2 agents and had sales of \$200,000, or \$100,000 per agent. An agent was added to the sales force in March (making 3) and then one more was added in May (making 4). This leaves 4 agents on the sales force for June, when the dealership sold \$800,000 or \$200,000 per agent (\$800,000/4). We can find the percent difference by dividing the difference between the two per-agent amounts by the per-agent amount in January:
Percent Difference = (\$200,000 – \$100,000) / (\$100,000)= 100,000 ÷ 100,000 = 1 or 100%. The correct answer is choice (B).

The trap answer is choice (D). \$200,000 per agent is double \$100,000 per agent. But remember that the question asks for the percent increase. \$200,000 represents 200% of \$100,000, but only 100% more than \$100,000.
-------------

In this question in May the chart says 900,000 not 800,000 which would make the answer C.