The product of the squares of two positive integers is 100. How many pairs of positive integers satisfy this condition?
A. 0 B. 1 C. 2 D. 3 E. 4
(C) 100 = 2 × 2 × 5 × 5.
The only possible combination of the prime factors that make the product of two squares is 2² × 5² = 100. Besides, 100 is the square of the positive integer itself so 10² × 1² = 100.
There are two possible pairs of positive integers that satisfy the condition: (1, 10) and (2, 5).
The correct answer is choice (C). 
The answer is wrong. The product of the squares of two other positive inegers is also 100: 8 & 6. 64 + 36=100.
