**Quote:**

In this question, we do not know whether *r* is greater than 10 …

The question statement implies that

*r* is greater than 12.

The average value of a set of numbers lies between the largest and the smallest. We have pumpkins of two weights 10 and

*r*. So the average lies somewhere between 10 and

*r*.

We know that this average is 12. So 12 is somewhere between 10 and

*r*. Thus,

*r* is greater than 12.

**Quote:**

Therefore, my answer to this question would be E as I do not know whether *x* = *y*/4 or *y* = *x*/4 .

Even if you didn't deduce the above fact logically, plug in

*y* =

*x*/4 to see that it does not fit.

As we know,

*r* = 12 + 2

*x*/

*y* , so for

*y* =

*x*/4 we get

*r* = 12 + 8

*r* = 20

Remember,

*y* =

*x*/4 arose from the assumption that

*r* is less than 10, but

*r* = 20 is greater than 10, so that assumption is not possible.