A similar question:

http://800score.com/forum/viewtopic.php?t=129----------

Four packages have an average weight of 10.5 pounds. What is the minimum possible weight of the heaviest package in pounds if the median is 10 pounds?

A. 10

B. 10.5

C. 11

D. 12

E. 13

(D) Let us denote the weights of the packages in pounds by

*v*,

*x*,

*y*,

*z* naming from the lightest one to the heaviest one. The median is 10 pounds. Therefore (

*x* +

*y*) / 2 = 10.

*x* +

*y* = 20

The average is 10.5 pounds. Therefore (

*v* +

*x* +

*y* +

*z*) / 4 = 10.5.

*v* + (

*x* +

*y*) +

*z* = 42

*v* + 20 +

*z* = 42

*v* +

*z* = 22

The weight

*v* must be no greater than 10, since 10 is the median. Therefore the minimum possible weight of the heaviest package is 22 – 10 = 12 pounds (all the other packages would weigh 10 pounds in this case).

The correct answer is (D).

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**I would think the answer could also be 13 as the lightest package should be less than 10 (in this case could be 9)?**