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 Post subject: GRE Arithmetic (Select One)Posted: Tue Sep 14, 2010 2:58 am

Joined: Sun May 30, 2010 3:15 am
Posts: 424
A prize of \$600 is to be distributed among 20 winners, each of whom must be awarded at least \$20. If 2/5 of the prize will be distributed to 3/5 of the winners, what is the greatest possible individual award?
A. \$20
B. \$25
C. \$45
D. \$220
E. \$300

(D) We are told that 2/5 of the prize is distributed to 3/5 of the winners:
2/5 of the prize = 2/5 × \$600 = \$240.
3/5 of the winners = 3/5 × 20 = 12 winners.
Since \$240/12 = \$20, we know that each of these people received the minimum of \$20.

The remaining \$360 will be divided among the 8 remaining winners. For one of these winners to receive the greatest possible award, the other seven winners must receive the minimum \$20. These seven winners receive a total of: 7 × \$20 = \$140.

The eighth winner would receive all the remaining prize money:\$360 – \$140 = \$220.

The correct answer is choice (D).
-------------

In the above question, you calculate a minimum of \$20 to be distributed among the "12" people to whom \$240 would be distributed. Then you claim that that \$20 is also a minimum for the remaining 8 winners. It seems that the minimum amount that each of the remaining 8 winners could receive is 360/8 = \$45.

So for one of these 8 winners to receive the greatest possible award, the remaining 7 winners must receive 7 × \$45 (not \$20) = \$315.

So the eighth winner would receive the remaining of the prize:
\$360 – \$315 = \$45

(\$240 + \$315 + \$45 = \$600)

Please explain if my logic is flawed.
Thank you.

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 Post subject: Re: math (test 4, question 5): arithmetic, logic.Posted: Tue Sep 14, 2010 3:24 am

Joined: Sun May 30, 2010 2:23 am
Posts: 498

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