When 28 is divided by the positive integer x, the remainder is 1. What is the sum of all the possible values of x for which this is true? A. 2 B. 3 C. 9 D. 30 E. 39

(E) First, we must find which numbers leave a remainder of 1. These numbers must be divisors of 27 (which is 1 less than 28) greater than 1. Such divisors of 27 are 3, 9, 27.

The first number is 3: 28/3 = 9, remainder 1. The next number after that is 9: 28/9 = 3, remainder 1. 27 also gives a remainder of 1, giving 3 possible values for x.

Adding these three values, we get 3 + 9 + 27 = 39.

The correct answer is choice (E). -------------

Why we need to add all the three possible divident for this question?

Users browsing this forum: No registered users and 3 guests

You cannot post new topics in this forum You cannot reply to topics in this forum You cannot edit your posts in this forum You cannot delete your posts in this forum You cannot post attachments in this forum