1. Sets
A set is a group of distinct objects, called elements or members. Sets are used to look at the descriptions and interactions of the elements.
Elements are typically listed in {brackets}. The best way to visualize a set is with a Venn diagram. Use overlapping circles to organize the elements of a set.
The set Animals contains the subset Mammals.
In the set of Mammals, Dogs and Cats are subsets.
Lizards are animals outside of the set Mammals.
The set S = {1, 3, 5, 7, 9} is the odd integers less than 10.
The set P = {2, 3, 5, 7} is the prime numbers less than 10.
The intersection is composed of the numbers that are in both sets {3, 5, 7}.
2. Number of Elements
Counting problems are one type of set questions. These questions can ask about the number of elements in the set or subsets.
After school, 20 students play soccer, 10 play basketball, and 7 play both. How many students play basketball, soccer or both?
(A) 20
(B) 22
(C) 23
(D) 25
(E) 29
Solution
Method 1
Draw a diagram. First put the overlap into the diagram. Then calculate the number in each subset.
For only playing basketball, 10 − 7 = 3. For only playing soccer, 20 − 7 = 13.
So the total number of players is basketball only + soccer only + both = 3 + 13 + 7 = 23.
The correct answer is option (C).
Method 2
Another method to find the total number in a set is to add the number in each subset and subtract the number in the intersection.
subset + subset − intersection = total elements in set
20 + 10 − 7 = 23
The correct answer is option (C).
Out of 50 people at a buffet dinner, 14 chose ice cream for dessert, 25 chose chocolate cake, and 5 chose both.
(a) How many people had dessert?
(b) How many people chose not to have dessert?
(b) What percent of the people at the dinner had only cake?
Solution
Draw a diagram. First put the overlap number into the diagram. The 5 people who had both are included in both of the 2 sets. Then calculate the number in each subset.
For the number of people who only had ice cream, subtract the people who had both.
14 − 5 = 9
For the number of people who only had cake, 25 − 5 = 20.
(a) The number of people who had dessert is 20 + 5 + 9 = 34.
(b) Out of the 50 people, 50 − 34 = 16 people did not have dessert.
(c) The diagram shows 20 people had only cake, out of the 50 people at the dinner.
So it is 20/50 = 40/100 = 40%.
Solution
Draw a diagram.
First put the overlap number into the diagram. Calculate the number in each subset by subtracting the numbers already in the intersection.
all 3 pets = 2 people
cat and dog = 6 – 2 = 4
dog and other = 4 – 2 = 2
cat and other = 3 – 2 = 1
cat only = 16 – 4 – 1 – 2 = 9
dog only = 22 – 4 – 2 – 2 = 14
other type only = 9 – 2 – 1 – 2 = 4
The total number of students in the circles is
9 + 4 + 14 + 1 + 2 + 2 + 4 = 36
If there are 40 students in the class, 40 – 36 = 4 students have no pets.
4 out of 40 = 4/40 = 1/10 = 10/100.
10% of the students have no pets.
Solution
Method 1
Draw a diagram. You are looking for the intersection of trucks and white.
The total number of vehicles is 36.
There are 14 that are neither trucks nor white. This number goes outside the circles.
The total number of trucks is 22.
The total number of white vehicles is 10.
So there are 36 vehicles = 14 neither + (22 trucks + 10 white – intersection)
36 = 14 + (22 + 10 – x)
22 = 32 – x
-10 = –x
So the intersection of trucks and white is 10. There are 10 white trucks.
Method 2
Use a table. The bottom row and the right column must each add to 36.
Start with the given information.
white
not white
truck
total trucks = 22
car
14 cars
total white = 10
total vehicles = 36
Fill in 2 more numbers using the totals for each column and row.
(B) 150
(C) 200
(D) 250
(E) 400
Solution
Draw a diagram. You are looking for the areas that are not intersections of the plans.
Notice that the intersections are each counted twice:
The intersection of work and relax is included in the total count of work (175) and in the total count of relax (105).
So the answer is the number of students in each set minus twice the sum of the intersections.
175 + 120 + 105 − 2(150) = 400 − 300 = 100
The correct answer is option (A).
Solution
Method 1
You are looking for the percentage of jack-o’-lanterns with noses. Use n% to represent the percent of jack-o’-lanterns with noses.
The first step is to draw a diagram. The sets are jack-o’-lanterns with noses and jack-o’-lanterns that look friendly.
The total in the 2 sets is 100% of the jack-o’-lanterns.
20% looked friendly but had no nose, so 20% is the friendly set without the intersection.
Half of the jack-o’-lanterns with noses did not look friendly. So 0.5n% represents the percentage of jack-o’-lanterns that did not look friendly and the percentage that did look friendly.
So the percentage of jack-o’-lanterns who looked friendly is 20% + 0.5n% = 60%.
0.5n% = 40%
n% = 80%
80% of the jack-o’-lanterns had noses.
Method 2
Use a table. The bottom row and the right column must each add to 100%.
Start with the given information. Use n% to represent the percent of jack-o’-lanterns with noses.
Nose | No nose | ||
Friendly | 0.5n% | 20% | total friendly = 60% |
Not | 0.5n% | ||
total nose = n% | total = 100% |
Using just the first row of the table:
0.5n% + 20% = 60%
n% = 80%
80% of the jack-o’-lanterns had noses.
800score Tip: Count Inclusively
When doing counting problems, always be sure to count the first and last of the elements.
Solution
Each pair of post and rail covers 10 feet. So the fence needs 8 pairs of post and rail. But the trick here is to include the additional post that is needed at the end. The fence needs 8 rails and 9 posts.
(a) How many elements are in the set of integers from 5 to 20?
(b) What is the sum of the set of integers from 5 to 20?
Solution
(a) You might think you just subtract. Last − first = 15 − 5 = 10. But make a list.
{5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15} = 11 elements
Note: The formula for the number of consecutive integers in a sequence is (last − first) + 1, or L − F + 1.
(b) The first thing to notice is the sums of the pairings of the first and last elements of the set.
(first + last) = 5 + 15 = 20
(second + second to last) = 6 + 14 = 20
To use this pairing, you need to know the number of elements. For this set, there are 11 elements.
The sum will be (11 / 2)(20) = 5.5 × 20 = 110.
3. Using Sets
Some Examples above use information about the set to ask an additional question. Using sets as the basis for questions about probability, averages, and combinations/permutations is a second type of GMAT question that uses sets.
Solution
This is a question about permutations.
For a set with this few elements, a list is a simple method.
1, 2, 3, 4
1, 4, 3, 2
2, 3, 4, 1
2, 1, 4, 3
2, 1, 3, 4
2, 3, 1, 4
3, 2, 1, 4
3, 4, 1, 2
4, 1, 2, 3
4, 3, 2, 1
4, 3, 1, 2
4, 1, 3, 2
There are 12 arrangements.
(B) 30
(C) 40
(D) 45
(E) 60
Solution
Arithmetic mean: sum of elements/number of elements
Mode: the element that appears the most times in a set.
To find the value of k, use the arithmetic mean.
45 = 20 + 70 + 10 + k + 20 + 90/6
45 = 210 + k/6
45 × 6 = 210 + k
k = 270 – 210 = 60
With k = 60, rewrite the elements of the set in numerical order.
{10, 20, 20, 60, 70, 90}
The mode is 20, since it is the only element that appears more than once.
The correct answer is option (A).
Notice that the value of k is given as an answer option. A GMAT trick is to offer an answer option that is a number from a previous step in finding the real answer. The median is also given as an answer option. Since the number of elements is even, the median is the mean of the 2 center elements: (20 + 60)/2 = 40.
4. Range of Values
Range questions also refer to the elements in a set. When a question asks for a possible range, be sure to check both the lowest and highest possible values.
Solution
First find the lowest value.
Three bottles and 30 mushrooms is the fewest number of mushrooms in the box.
3 × 30 × 10% = 90 × 0.1 = 9 At least 9 flawed mushrooms.
Then find the greatest value.
Five bottles and 40 mushrooms is the greatest number of mushrooms in the box.
5 × 40 × 10% = 200 × 0.1 = 20 At most 20 flawed mushrooms.
There are between 9 and 20 flawed mushrooms in the bottles in the box.
What is the range of values for the product of elements ab?
Solution
Find the minimum values and multiply.
The minimum value in set A is 1 and the minimum value in set B is 6, so the minimum for ab is 1 × 6 = 6.
Find the maximum values and multiply.
The maximum value in set A is 4. Set B has no maximum, so ab has no maximum.
The range values for the product of Set A and Set B is ab > 6.
Video Quiz
Sets
Best viewed in landscape mode
6 questions with video explanations
100 seconds per question
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https://www.youtube.com/watch?v=XAVPvudc9L4
https://www.youtube.com/watch?v=DjPfRTEPH78
https://www.youtube.com/watch?v=InkzfUSRB1s
https://www.youtube.com/watch?v=ptRuHtzF5hk
https://www.youtube.com/watch?v=hAzYVLlXF6k
https://www.youtube.com/watch?v=2HN3NzH8WkQ
https://www.youtube.com/watch?v=uE_aMa_W0o0&list=PL6F58D00ADB3C0A85&index=9
Before attempting these problems, be sure to review this section on data sufficiency questions.
https://www.youtube.com/watch?v=Qrm5f92upTk
https://www.youtube.com/watch?v=cz1bfvHD3ws
https://www.youtube.com/watch?v=GA7yqlV6KGA
https://www.youtube.com/watch?v=esJS_NsJPA8
https://www.youtube.com/watch?v=9bIPTygO4-Y
https://www.youtube.com/watch?v=aWcAELf8fHM
https://www.youtube.com/watch?v=CdUKAdGi0sA